What is expand (e^0+sin(0)-1)/(ln(1+0)) ?

The solution to expand (e^0+sin(0)-1)/(ln(1+0)) is Undefined

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expand (e^0+sin(0)-1)/(ln(1+0))

expand

\frac{e ^{0} + sin ( 0 ) - 1}{ln ( 1 + 0 )}

Undefined

Solution steps

\frac{e ^{0} + sin ( 0 ) - 1}{ln ( 1 + 0 )}

ln (1 + 0) = 0

= \frac{e ^{0} + sin ( 0 ) - 1}{0}

\frac{x}{0}

is undefined

= Undefined

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π (x - 2)^{2} \cdot (3 x - 4)

(2 x - y = H (x, y)) d H (x, y)

\frac{( 16 - x ) ^{2} x}{32}

(1 + cos (x))^{4} \cdot sin (x)

What is expand (e^0+sin(0)-1)/(ln(1+0)) ?
The solution to expand (e^0+sin(0)-1)/(ln(1+0)) is Undefined