What is expand E(x)(ax^1+b|x^2=x^2|) ?

The solution to expand E(x)(ax^1+b|x^2=x^2|) is ax^1E(x)+b|=x^2x^2|E(x)

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expand E(x)(ax^1+b|x^2=x^2|)

expand

E (x) (a x^{1} + b x^{2} = x^{2})

a x^{1} E (x) + b = x^{2} x^{2} E (x)

Solution steps

E (x) (a x^{1} + b x^{2} = x^{2})

= E (x) (a x^{1} + b = x^{2} x^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = E (x), b = a x^{1}, c = b x^{2} = x^{2}

= E (x) a x^{1} + E (x) b x^{2} = x^{2}

= a x^{1} E (x) + b = x^{2} x^{2} E (x)

\frac{( 2 ( n + 1 ) ) !}{2 ^{n + 1} ( n + 1 ) ! ( n + 1 )}

\frac{- x ^{2} + 2 x + 3}{( x ^{2} + 3 ) ^{2}}

\frac{20 ( 249 - 2 )}{49}

(x^{3} - 4 x^{2} + x - 4) (x^{2} = 18 x + 82)

\frac{( x ) ( 2 x + 1 )}{2}

What is expand E(x)(ax^1+b|x^2=x^2|) ?
The solution to expand E(x)(ax^1+b|x^2=x^2|) is ax^1E(x)+b|=x^2x^2|E(x)