What is expand ((x+1)(x+2)(x-2))/(x-1) ?

The solution to expand ((x+1)(x+2)(x-2))/(x-1) is (x^3-4x+x^2-4)/(x-1)

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expand ((x+1)(x+2)(x-2))/(x-1)

expand

\frac{( x + 1 ) ( x + 2 ) ( x - 2 )}{x - 1}

\frac{x ^{3} - 4 x + x ^{2} - 4}{x - 1}

Solution steps

\frac{( x + 1 ) ( x + 2 ) ( x - 2 )}{x - 1}

Expand

(x + 1) (x + 2) (x - 2) : x^{3} - 4 x + x^{2} - 4

= \frac{x ^{3} - 4 x + x ^{2} - 4}{x - 1}

(5 x^{2} - 2 \cdot x^{2} - 1) x^{'}

\frac{( 0.5 s + 1 )}{( s + 1 ) ( 0.3 s + 1 )}

\frac{2 \cdot s}{( ( 1 + 0.5 \cdot s ) \cdot ( 1 + 0.125 \cdot s ) ^{2} )}

\frac{( x + 2 ) ( 2 x + 3 )}{3}

2 tan (x + y) sec^{2} (x + y) (1 + z)

What is expand ((x+1)(x+2)(x-2))/(x-1) ?
The solution to expand ((x+1)(x+2)(x-2))/(x-1) is (x^3-4x+x^2-4)/(x-1)