What is expand (4y^9)/(8y^3) ?

The solution to expand (4y^9)/(8y^3) is (y^6)/2

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expand (4y^9)/(8y^3)

expand

\frac{4 y ^{9}}{8 y ^{3}}

\frac{y ^{6}}{2}

Solution steps

\frac{4 y ^{9}}{8 y ^{3}}

Cancel the common factor:

4

= \frac{y ^{9}}{2 y ^{3}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{y ^{9}}{y ^{3}} = y^{9 - 3}

= \frac{y ^{9 - 3}}{2}

Subtract the numbers:

9 - 3 = 6

= \frac{y ^{6}}{2}

\frac{s - 1}{( s + 3 ) ( s ^{2} + 6 s + 13 )}

x^{2} + ((a + e) + (b + i)) x + (c + o)

\frac{x 2 ^{- x - 1} + 4 ^{- x - 1}}{x ( x + 1 )}

\frac{2 ( π ^{3} + 3 π ^{2} )}{3 π}

\frac{x - 1}{( x + 3 ) ( x - 6 )}