What are the solutions to the equation 4x^2+10x-5=0 ?

The solutions to the equation 4x^2+10x-5=0 are x=(-5+3sqrt(5))/4 ,x=-(5+3sqrt(5))/4

Find the zeros of 4x^2+10x-5=0

The zeros of 4x^2+10x-5=0 are x=(-5+3sqrt(5))/4 ,x=-(5+3sqrt(5))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 10 x - 5 = 0

x = \frac{- 5 + 3 5}{4}, x = - \frac{5 + 3 5}{4}

Solution steps

4 x^{2} + 10 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

1 0^{2} - 4 \cdot 4 (- 5) = 65

x_{1, 2} = \frac{- 10 \pm 6 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 10 + 6 5}{2 \cdot 4}, x_{2} = \frac{- 10 - 6 5}{2 \cdot 4}

x = \frac{- 10 + 6 5}{2 \cdot 4} : \frac{- 5 + 3 5}{4}

x = \frac{- 10 - 6 5}{2 \cdot 4} : - \frac{5 + 3 5}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 3 5}{4}, x = - \frac{5 + 3 5}{4}

12 t - 2 < - 5 t + 3612 t - 2 < - 5 t + 36

- 5 (4 x - 4) - 2 x - 4 = - 28

\frac{5 x ( x - 3 )}{2} = 3 (x - 5) + 6

2 j^{2} + 11 j + 12

5 x z - 5 yz - x + y

What are the solutions to the equation 4x^2+10x-5=0 ?
The solutions to the equation 4x^2+10x-5=0 are x=(-5+3sqrt(5))/4 ,x=-(5+3sqrt(5))/4
Find the zeros of 4x^2+10x-5=0
The zeros of 4x^2+10x-5=0 are x=(-5+3sqrt(5))/4 ,x=-(5+3sqrt(5))/4