What is factor 2j^2+11j+12 ?

The solution to factor 2j^2+11j+12 is (2j+3)(j+4)

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factor 2j^2+11j+12

factor

2 j^{2} + 11 j + 12

(2 j + 3) (j + 4)

Solution steps

2 j^{2} + 11 j + 12

Break the expression into groups

= (2 j^{2} + 3 j) + (8 j + 12)

Factor out

j

from

2 j^{2} + 3 j : j (2 j + 3)

Factor out

4

from

8 j + 12 : 4 (2 j + 3)

= j (2 j + 3) + 4 (2 j + 3)

Factor out common term

2 j + 3

= (2 j + 3) (j + 4)

5 x z - 5 yz - x + y

x^{2} + 8 x = - 12

(x - 5) (x + 1) = 0

3 x^{2} + 22 x + 7

(4 a^{2} b)^{4} (\frac{- a ^{3}}{2 b})^{2}