What is 12t-2<-5t+3612t-2<-5t+36 ?

The solution to 12t-2<-5t+3612t-2<-5t+36 is 0<t< 19/1806

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12t-2<-5t+3612t-2<-5t+36

12 t - 2 < - 5 t + 3612 t - 2 < - 5 t + 36

0 < t < \frac{19}{1806}

Interval Notation

(0, \frac{19}{1806})

Decimal Notation

0 < t < 0.01052 \dots

Solution steps

12 t - 2 < - 5 t + 3612 t - 2 < - 5 t + 36

a < u < b

then

a < u and u < b

12 t - 2 < - 5 t + 3612 t - 2 and - 5 t + 3612 t - 2 < - 5 t + 36

12 t - 2 < - 5 t + 3612 t - 2 : t > 0

- 5 t + 3612 t - 2 < - 5 t + 36 : t < \frac{19}{1806}

Combine the intervals

t > 0 and t < \frac{19}{1806}

Merge Overlapping Intervals

0 < t < \frac{19}{1806}

- 5 (4 x - 4) - 2 x - 4 = - 28

\frac{5 x ( x - 3 )}{2} = 3 (x - 5) + 6

2 j^{2} + 11 j + 12

5 x z - 5 yz - x + y

x^{2} + 8 x = - 12

What is 12t-2<-5t+3612t-2<-5t+36 ?
The solution to 12t-2<-5t+3612t-2<-5t+36 is 0<t< 19/1806