What are the solutions to the equation x^2+8x=-12 ?

The solutions to the equation x^2+8x=-12 are x=-2,x=-6

Find the zeros of x^2+8x=-12

The zeros of x^2+8x=-12 are x=-2,x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 8 x = - 12

x = - 2, x = - 6

Solution steps

x^{2} + 8 x = - 12

Move

12

to the left side

x^{2} + 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 12 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 1}, x_{2} = \frac{- 8 - 4}{2 \cdot 1}

x = \frac{- 8 + 4}{2 \cdot 1} : - 2

x = \frac{- 8 - 4}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 2, x = - 6

(x - 5) (x + 1) = 0

3 x^{2} + 22 x + 7

(4 a^{2} b)^{4} (\frac{- a ^{3}}{2 b})^{2}

x^{4} y^{3} - x y^{2}

6^{2} + 1 2^{2} = x^{2}

What are the solutions to the equation x^2+8x=-12 ?
The solutions to the equation x^2+8x=-12 are x=-2,x=-6
Find the zeros of x^2+8x=-12
The zeros of x^2+8x=-12 are x=-2,x=-6