What is (-1/(x^2)+(12)/(x^4))(x^3-5x-1) ?

The solution to (-1/(x^2)+(12)/(x^4))(x^3-5x-1) is ((-x^2+12)(x^3-5x-1))/(x^4)

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simplify (-1/(x^2)+(12)/(x^4))(x^3-5x-1)

simplify

(- \frac{1}{x ^{2}} + \frac{12}{x ^{4}}) (x^{3} - 5 x - 1)

\frac{( - x ^{2} + 12 ) ( x ^{3} - 5 x - 1 )}{x ^{4}}

Solution steps

(- \frac{1}{x ^{2}} + \frac{12}{x ^{4}}) (x^{3} - 5 x - 1)

Join

- \frac{1}{x ^{2}} + \frac{12}{x ^{4}} : \frac{- x ^{2} + 12}{x ^{4}}

= \frac{- x ^{2} + 12}{x ^{4}} (x^{3} - 5 x - 1)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - x ^{2} + 12 ) ( x ^{3} - 5 x - 1 )}{x ^{4}}

cos (3 t - 3) u (t - 1) + t^{3} u (t - 2)

\frac{d}{d r ( T )} ((E (r, T)) (10 - (10 T) (b^{- 0.14 r (T)})))

\frac{x ^{3} - 3 x ^{2}}{( x - 1 ) ^{3}}

(lo g_{10} (x)) (x + 1) (x + 2) (x + 3)

\frac{x ( x - y ln ( x ) )}{y ( y - x ln ( y ) )}

What is (-1/(x^2)+(12)/(x^4))(x^3-5x-1) ?
The solution to (-1/(x^2)+(12)/(x^4))(x^3-5x-1) is ((-x^2+12)(x^3-5x-1))/(x^4)