What is expand (sin(2x)+1)^2 ?

The solution to expand (sin(2x)+1)^2 is sin^2(2x)+2sin(2x)+1

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expand (sin(2x)+1)^2

expand

(sin (2 x) + 1)^{2}

sin^{2} (2 x) + 2 sin (2 x) + 1

Solution steps

(sin (2 x) + 1)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(sin (2 x) + 1)^{2} = sin^{2} (2 x) + 2 sin (2 x) \cdot 1 + 1^{2}

= sin^{2} (2 x) + 2 sin (2 x) \cdot 1 + 1^{2}

Simplify

sin^{2} (2 x) + 2 sin (2 x) \cdot 1 + 1^{2} : sin^{2} (2 x) + 2 sin (2 x) + 1

= sin^{2} (2 x) + 2 sin (2 x) + 1

4 (6 - x - 2 (3 - x - 5 = 9 (5 - 2 x)))

\frac{2 x - 6}{3 ( x ^{2} - 6 x + 5 ) ^{\frac{2}{3}}}

10 [lo g_{10} (\frac{I}{1 0 ^{- 12}})]

(2 p - 0.8) (2 p - 0, 5)

What is expand (sin(2x)+1)^2 ?
The solution to expand (sin(2x)+1)^2 is sin^2(2x)+2sin(2x)+1