What is expand (x^3+1/(x^3))^2 ?

The solution to expand (x^3+1/(x^3))^2 is (x^{12}+2x^6+1)/(x^6)

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expand (x^3+1/(x^3))^2

expand

(x^{3} + \frac{1}{x ^{3}})^{2}

\frac{x ^{12} + 2 x ^{6} + 1}{x ^{6}}

Solution steps

(x^{3} + \frac{1}{x ^{3}})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(x^{3} + \frac{1}{x ^{3}})^{2} = (x^{3})^{2} + 2 x^{3} \frac{1}{x ^{3}} + (\frac{1}{x ^{3}})^{2}

= (x^{3})^{2} + 2 x^{3} \frac{1}{x ^{3}} + (\frac{1}{x ^{3}})^{2}

Simplify

(x^{3})^{2} + 2 x^{3} \frac{1}{x ^{3}} + (\frac{1}{x ^{3}})^{2} : \frac{x ^{12} + 2 x ^{6} + 1}{x ^{6}}

= \frac{x ^{12} + 2 x ^{6} + 1}{x ^{6}}

(e^{2 x} - 1) (e^{2 x} + 1)

(- 12 mn + 5) l e f t (- 3 mn - 2)

(a - 3 x - 2) x (a + 3 x - 2)

\frac{x ^{2} + 6}{2 x + 1} - \frac{1}{2} x

12 (1 - \frac{0.87}{π})

What is expand (x^3+1/(x^3))^2 ?
The solution to expand (x^3+1/(x^3))^2 is (x^{12}+2x^6+1)/(x^6)