What is expand (s+1)/((s+2)(s-3)) ?

The solution to expand (s+1)/((s+2)(s-3)) is (s+1)/(s^2-s-6)

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expand (s+1)/((s+2)(s-3))

expand

\frac{s + 1}{( s + 2 ) ( s - 3 )}

\frac{s + 1}{s ^{2} - s - 6}

Solution steps

\frac{s + 1}{( s + 2 ) ( s - 3 )}

Expand

(s + 2) (s - 3) : s^{2} - s - 6

= \frac{s + 1}{s ^{2} - s - 6}

(z - 1 - i) (z - 1 + i)

(L - \frac{t}{2}) (r) (H + \frac{k}{2})^{2}

\frac{1}{s ( s + 1 ) ( s ^{2} + 6 s + 13 )}

\frac{x x ^{2} + 36 \cdot 3 - 2 ( x ^{2} + 36 )}{6 ( x ^{2} + 36 )}

ln (4) m^{3} n^{5}

What is expand (s+1)/((s+2)(s-3)) ?
The solution to expand (s+1)/((s+2)(s-3)) is (s+1)/(s^2-s-6)