What are the solutions to the equation 4(x+2)^2=4 ?

The solutions to the equation 4(x+2)^2=4 are x=-1,x=-3

Find the zeros of 4(x+2)^2=4

The zeros of 4(x+2)^2=4 are x=-1,x=-3

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4 (x + 2)^{2} = 4

x = - 1, x = - 3

Solution steps

4 (x + 2)^{2} = 4

Divide both sides by

4

(x + 2)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 1 : x = - 1

Solve

x + 2 = - 1 : x = - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

\frac{5}{a ^{2} + 3 a + 2} + \frac{5 a + 1}{a ^{2} + 3 a + 2}

18 \leq 3 (b - 4)

- 4 (\frac{x + 1}{4}) > x - 8 (\frac{2}{3 - x})

- y^{2} + yz - x y

\frac{1}{2} 9

What are the solutions to the equation 4(x+2)^2=4 ?
The solutions to the equation 4(x+2)^2=4 are x=-1,x=-3
Find the zeros of 4(x+2)^2=4
The zeros of 4(x+2)^2=4 are x=-1,x=-3