What is expand (x^2+2)/((x-2)(x-3)(x-4)) ?

The solution to expand (x^2+2)/((x-2)(x-3)(x-4)) is (x^2+2)/(x^3-9x^2+26x-24)

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expand (x^2+2)/((x-2)(x-3)(x-4))

expand

\frac{x ^{2} + 2}{( x - 2 ) ( x - 3 ) ( x - 4 )}

\frac{x ^{2} + 2}{x ^{3} - 9 x ^{2} + 26 x - 24}

Solution steps

\frac{x ^{2} + 2}{( x - 2 ) ( x - 3 ) ( x - 4 )}

Expand

(x - 2) (x - 3) (x - 4) : x^{3} - 9 x^{2} + 26 x - 24

= \frac{x ^{2} + 2}{x ^{3} - 9 x ^{2} + 26 x - 24}

32 e^{t} \cdot U (t - 4)

3 - (2 - 3)^{2}

p^{\frac{1}{5}} (p^{\frac{4}{5}} + 4 p^{\frac{9}{5}})

(n + 1) (\frac{n ( 2 n + 1 )}{6} + 1)

\frac{10 ( 5 + 1985 )}{49}

What is expand (x^2+2)/((x-2)(x-3)(x-4)) ?
The solution to expand (x^2+2)/((x-2)(x-3)(x-4)) is (x^2+2)/(x^3-9x^2+26x-24)