What is expand (2x-5)/((2x-4)(x-4)(x-5)) ?

The solution to expand (2x-5)/((2x-4)(x-4)(x-5)) is (2x-5)/(2x^3-22x^2+76x-80)

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expand (2x-5)/((2x-4)(x-4)(x-5))

expand

\frac{2 x - 5}{( 2 x - 4 ) ( x - 4 ) ( x - 5 )}

\frac{2 x - 5}{2 x ^{3} - 22 x ^{2} + 76 x - 80}

Solution steps

\frac{2 x - 5}{( 2 x - 4 ) ( x - 4 ) ( x - 5 )}

Expand

(2 x - 4) (x - 4) (x - 5) : 2 x^{3} - 22 x^{2} + 76 x - 80

= \frac{2 x - 5}{2 x ^{3} - 22 x ^{2} + 76 x - 80}

\frac{- 4 x ^{3} + 1}{2 x ^{\frac{1}{2}} ( x ^{3} + 1 ) ^{2}}

(x + 3) (x + 1) (0.2 x) (\frac{1}{2})

(2 x^{3} + 9 x^{2} + 3 x - 4) d i v i d e (x + 4)

\frac{d}{d x} ((f (x, y)) f (x, y) (x^{3} - 3 x y + y^{2}))

\frac{\partial}{\partial t} ((x) (x^{2} + y^{2}))

What is expand (2x-5)/((2x-4)(x-4)(x-5)) ?
The solution to expand (2x-5)/((2x-4)(x-4)(x-5)) is (2x-5)/(2x^3-22x^2+76x-80)