What is expand (x+3)(x+1)(0.2x)(1/2) ?

The solution to expand (x+3)(x+1)(0.2x)(1/2) is (x^3}{10}+(2x^2)/5+\frac{3x)/(10)

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expand (x+3)(x+1)(0.2x)(1/2)

expand

(x + 3) (x + 1) (0.2 x) (\frac{1}{2})

\frac{x ^{3}}{10} + \frac{2 x ^{2}}{5} + \frac{3 x}{10}

Solution steps

(x + 3) (x + 1) (0.2 x) (\frac{1}{2})

Apply rule:

(a) = a

(\frac{1}{2}) = \frac{1}{2}

= (x + 3) (x + 1) \cdot 0.2 x \frac{1}{2}

= \frac{1}{2} \cdot 0.2 x (x + 3) (x + 1)

Apply FOIL method

(x + 3) (x + 1) : x^{2} + 4 x + 3

= \frac{1}{2} \cdot 0.2 x (x^{2} + 4 x + 3)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

\frac{1}{2} \cdot 0.2 x (x^{2} + 4 x + 3) = \frac{1}{2} \cdot 0.2 x x^{2} + \frac{1}{2} \cdot 0.2 x \cdot 4 x + \frac{1}{2} \cdot 0.2 x \cdot 3

= \frac{1}{2} \cdot 0.2 x x^{2} + \frac{1}{2} \cdot 0.2 x \cdot 4 x + \frac{1}{2} \cdot 0.2 x \cdot 3

Simplify

\frac{1}{2} \cdot 0.2 x x^{2} + \frac{1}{2} \cdot 0.2 x \cdot 4 x + \frac{1}{2} \cdot 0.2 x \cdot 3 : \frac{x ^{3}}{10} + \frac{2 x ^{2}}{5} + \frac{3 x}{10}

= \frac{x ^{3}}{10} + \frac{2 x ^{2}}{5} + \frac{3 x}{10}

(2 x^{3} + 9 x^{2} + 3 x - 4) d i v i d e (x + 4)

\frac{d}{d x} ((f (x, y)) f (x, y) (x^{3} - 3 x y + y^{2}))

\frac{\partial}{\partial t} ((x) (x^{2} + y^{2}))

\frac{K}{x ( 1 - x T )}

(x^{2} + 1) y^{'} (x) + x y - 2 x

What is expand (x+3)(x+1)(0.2x)(1/2) ?
The solution to expand (x+3)(x+1)(0.2x)(1/2) is (x^3}{10}+(2x^2)/5+\frac{3x)/(10)