What is expand (6s^3-8s^2-9s+18)/(s^3(s-2)) ?

The solution to expand (6s^3-8s^2-9s+18)/(s^3(s-2)) is (6s^3-8s^2-9s+18)/(s^4-2s^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (6s^3-8s^2-9s+18)/(s^3(s-2))

expand

\frac{6 s ^{3} - 8 s ^{2} - 9 s + 18}{s ^{3} ( s - 2 )}

\frac{6 s ^{3} - 8 s ^{2} - 9 s + 18}{s ^{4} - 2 s ^{3}}

Solution steps

\frac{6 s ^{3} - 8 s ^{2} - 9 s + 18}{s ^{3} ( s - 2 )}

Expand

s^{3} (s - 2) : s^{4} - 2 s^{3}

= \frac{6 s ^{3} - 8 s ^{2} - 9 s + 18}{s ^{4} - 2 s ^{3}}

\frac{( 2 - x ) ( x - 3 ) ( x - 4 ) \cdot 7}{24}

x (3 x - 5)

x^{\frac{1}{3}} (x^{2} + 4)

(2 x + 1) \cdot ln (2 x + 1)

- sin (x) \cdot (6 (2 x + 1)^{2})

What is expand (6s^3-8s^2-9s+18)/(s^3(s-2)) ?
The solution to expand (6s^3-8s^2-9s+18)/(s^3(s-2)) is (6s^3-8s^2-9s+18)/(s^4-2s^3)