What are the solutions to the equation 4x(x+1)=15 ?

The solutions to the equation 4x(x+1)=15 are x= 3/2 ,x=-5/2

Find the zeros of 4x(x+1)=15

The zeros of 4x(x+1)=15 are x= 3/2 ,x=-5/2

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4 x (x + 1) = 15

x = \frac{3}{2}, x = - \frac{5}{2}

Solution steps

4 x (x + 1) = 15

Expand

4 x (x + 1) : 4 x^{2} + 4 x

4 x^{2} + 4 x = 15

Move

15

to the left side

4 x^{2} + 4 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 15) = 16

x_{1, 2} = \frac{- 4 \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 16}{2 \cdot 4}, x_{2} = \frac{- 4 - 16}{2 \cdot 4}

x = \frac{- 4 + 16}{2 \cdot 4} : \frac{3}{2}

x = \frac{- 4 - 16}{2 \cdot 4} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{5}{2}

x^{2} = 7 x + 30

- 16 t^{2} + 80 t + 32 = 0

\frac{6 n}{5} + \frac{1}{2} = \frac{9 n - 1}{10}

0. 5^{\frac{1}{3}}

\frac{a ^{2} b ^{- 7}}{a ^{- 4} b ^{- 2}}

What are the solutions to the equation 4x(x+1)=15 ?
The solutions to the equation 4x(x+1)=15 are x= 3/2 ,x=-5/2
Find the zeros of 4x(x+1)=15
The zeros of 4x(x+1)=15 are x= 3/2 ,x=-5/2