What is expand log_{2}((4x+1)/x) ?

The solution to expand log_{2}((4x+1)/x) is log_{2}(4x+1)-log_{2}(x)

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expand log_{2}((4x+1)/x)

expand

lo g_{2} (\frac{4 x + 1}{x})

lo g_{2} (4 x + 1) - lo g_{2} (x)

Solution steps

lo g_{2} (\frac{4 x + 1}{x})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{2} (\frac{4 x + 1}{x}) = lo g_{2} (4 x + 1) - lo g_{2} (x)

= lo g_{2} (4 x + 1) - lo g_{2} (x)

lo g_{5} (\frac{3 x ^{2}}{y ^{3}})

ln (\frac{7}{3})

\frac{1}{2} (6 ln (x) - 7 ln (y))

\frac{1}{3} lo g_{c} (x) + 5 lo g_{c} (y) - 3 lo g_{c} (x)

lo g_{10} (x + 1) + lo g_{10} (x - 1)

What is expand log_{2}((4x+1)/x) ?
The solution to expand log_{2}((4x+1)/x) is log_{2}(4x+1)-log_{2}(x)