What is 20log_{6}(u)+5log_{6}(v) ?

The solution to 20log_{6}(u)+5log_{6}(v) is log_{6}(u^{20}v^5)

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simplify 20log_{6}(u)+5log_{6}(v)

simplify

20 lo g_{6} (u) + 5 lo g_{6} (v)

lo g_{6} (u^{20} v^{5})

Solution steps

20 lo g_{6} (u) + 5 lo g_{6} (v)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

20 lo g_{6} (u) = lo g_{6} (u^{20})

= lo g_{6} (u^{20}) + 5 lo g_{6} (v)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

5 lo g_{6} (v) = lo g_{6} (v^{5})

= lo g_{6} (u^{20}) + lo g_{6} (v^{5})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{6} (u^{20}) + lo g_{6} (v^{5}) = lo g_{6} (u^{20} v^{5})

= lo g_{6} (u^{20} v^{5})

ln (8) + ln (x) + ln (y)

lo g_{9} (\frac{u ^{2}}{s ^{3} t ^{4}})

lo g_{b} (x) + lo g_{b} (x + 2) - lo g_{b} (8)

lo g_{5} (\frac{x ^{2}}{y ^{2} z ^{3}})

- lo g_{10} (3.5 \cdot 1 0^{- 5})

What is 20log_{6}(u)+5log_{6}(v) ?
The solution to 20log_{6}(u)+5log_{6}(v) is log_{6}(u^{20}v^5)