What is 2log_{b}(y)+6log_{b}(z) ?

The solution to 2log_{b}(y)+6log_{b}(z) is log_{b}(y^2z^6)

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simplify 2log_{b}(y)+6log_{b}(z)

simplify

2 lo g_{b} (y) + 6 lo g_{b} (z)

lo g_{b} (y^{2} z^{6})

Solution steps

2 lo g_{b} (y) + 6 lo g_{b} (z)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{b} (y) = lo g_{b} (y^{2})

= lo g_{b} (y^{2}) + 6 lo g_{b} (z)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

6 lo g_{b} (z) = lo g_{b} (z^{6})

= lo g_{b} (y^{2}) + lo g_{b} (z^{6})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{b} (y^{2}) + lo g_{b} (z^{6}) = lo g_{b} (y^{2} z^{6})

= lo g_{b} (y^{2} z^{6})

ln^{2} (x) - ln (x)

ln (x) - 4 [ln (x + 2) + ln (x - 2)]

2 lo g_{b} (a) + 3 lo g_{b} (c^{2}) - 4 lo g_{b} (d)

lo g_{4} (a^{3} b^{3} \cdot c)

- 0.7 lo g_{2} (0.7) - 0.3 lo g_{2} (0.3)

What is 2log_{b}(y)+6log_{b}(z) ?
The solution to 2log_{b}(y)+6log_{b}(z) is log_{b}(y^2z^6)