What is ln(x)-4[ln(x+2)+ln(x-2)] ?

The solution to ln(x)-4[ln(x+2)+ln(x-2)] is ln(x)-4ln((x+2)(x-2))

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simplify ln(x)-4[ln(x+2)+ln(x-2)]

simplify

ln (x) - 4 [ln (x + 2) + ln (x - 2)]

ln (x) - 4 ln ((x + 2) (x - 2))

Solution steps

ln (x) - 4 [ln (x + 2) + ln (x - 2)]

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (x + 2) + ln (x - 2) = ln ((x + 2) (x - 2))

= ln (x) - 4 [ln ((x + 2) (x - 2))]

Remove parentheses:

(a) = a

= ln (x) - 4 ln ((x + 2) (x - 2))

2 lo g_{b} (a) + 3 lo g_{b} (c^{2}) - 4 lo g_{b} (d)

lo g_{4} (a^{3} b^{3} \cdot c)

- 0.7 lo g_{2} (0.7) - 0.3 lo g_{2} (0.3)

lo g_{7} (x + 1) - lo g_{7} (\frac{1}{x + 1})

ln (3 ab \cdot 5 c)

What is ln(x)-4[ln(x+2)+ln(x-2)] ?
The solution to ln(x)-4[ln(x+2)+ln(x-2)] is ln(x)-4ln((x+2)(x-2))