What is log_{a}(40)+log_{a}(4) ?

The solution to log_{a}(40)+log_{a}(4) is log_{a}(160)

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simplify log_{a}(40)+log_{a}(4)

simplify

lo g_{a} (40) + lo g_{a} (4)

lo g_{a} (160)

Solution steps

lo g_{a} (40) + lo g_{a} (4)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{a} (40) + lo g_{a} (4) = lo g_{a} (40 \cdot 4)

= lo g_{a} (40 \cdot 4)

Multiply the numbers:

40 \cdot 4 = 160

= lo g_{a} (160)

lo g_{8} (x \cdot y \cdot z^{3})

ln (y \frac{y}{8 - y})

\frac{1}{2} (ln (8) x^{2} - ln (4) - 3 ln (x) - ln (y))

lo g_{3} (x) - lo g_{3} (y) - lo g_{3} (z)

5 lo g_{b} (x) + 6 lo g_{b} (z)

What is log_{a}(40)+log_{a}(4) ?
The solution to log_{a}(40)+log_{a}(4) is log_{a}(160)