What is log_{b}(x)+log_{b}(y)-log_{b}(u) ?

The solution to log_{b}(x)+log_{b}(y)-log_{b}(u) is log_{b}((xy)/u)

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simplify log_{b}(x)+log_{b}(y)-log_{b}(u)

simplify

lo g_{b} (x) + lo g_{b} (y) - lo g_{b} (u)

lo g_{b} (\frac{x y}{u})

Solution steps

lo g_{b} (x) + lo g_{b} (y) - lo g_{b} (u)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (x) + lo g_{b} (y) = lo g_{b} (x y)

= lo g_{b} (x y) - lo g_{b} (u)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{b} (x y) - lo g_{b} (u) = lo g_{b} (\frac{x y}{u})

= lo g_{b} (\frac{x y}{u})

\frac{1}{2} lo g_{b} (x) + 5 lo g_{b} (y) - 4 lo g_{b} (x)

lo g_{3} (x y)

ln (\frac{s ^{2} + 9}{s ^{2} + 64})

10 lo g_{10} (1.6 \cdot 1 0^{- 5}) + 120

6 ln (x) + ln (sin^{8} (x)) - ln (x^{2} + 1)

What is log_{b}(x)+log_{b}(y)-log_{b}(u) ?
The solution to log_{b}(x)+log_{b}(y)-log_{b}(u) is log_{b}((xy)/u)