What is log_{b}(2)+log_{b}(3) ?

The solution to log_{b}(2)+log_{b}(3) is log_{b}(6)

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simplify log_{b}(2)+log_{b}(3)

simplify

lo g_{b} (2) + lo g_{b} (3)

lo g_{b} (6)

Solution steps

lo g_{b} (2) + lo g_{b} (3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (2) + lo g_{b} (3) = lo g_{b} (2 \cdot 3)

= lo g_{b} (2 \cdot 3)

Multiply the numbers:

2 \cdot 3 = 6

= lo g_{b} (6)

- \frac{7}{8} lo g_{2} (\frac{7}{8}) - \frac{1}{8} lo g_{2} (\frac{1}{8})

lo g_{10} (\frac{x}{z ^{5} y ^{3}})

2 lo g_{b} (x) + 4 lo g_{b} (z)

3 ln (x) - \frac{1}{2} ln (y) + 1

3 lo g_{4} (x) + 5 lo g_{4} (y) - 6 lo g_{4} (z)

What is log_{b}(2)+log_{b}(3) ?
The solution to log_{b}(2)+log_{b}(3) is log_{b}(6)