What is simplify-7/8 log_{2}(7/8)-1/8 log_{2}(1/8) ?

The solution to simplify-7/8 log_{2}(7/8)-1/8 log_{2}(1/8) is -7/8 log_{2}(7/8)+3/8

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simplify-7/8 log_{2}(7/8)-1/8 log_{2}(1/8)

simplify

- \frac{7}{8} lo g_{2} (\frac{7}{8}) - \frac{1}{8} lo g_{2} (\frac{1}{8})

- \frac{7}{8} lo g_{2} (\frac{7}{8}) + \frac{3}{8}

Decimal Notation

0.54356 \dots

Solution steps

- \frac{7}{8} lo g_{2} (\frac{7}{8}) - \frac{1}{8} lo g_{2} (\frac{1}{8})

\frac{1}{8} lo g_{2} (\frac{1}{8}) = - \frac{3}{8}

= - \frac{7}{8} lo g_{2} (\frac{7}{8}) - (- \frac{3}{8})

Apply rule:

a - (- b) = a + b

- \frac{7}{8} lo g_{2} (\frac{7}{8}) - (- \frac{3}{8}) = - \frac{7}{8} lo g_{2} (\frac{7}{8}) + \frac{3}{8}

= - \frac{7}{8} lo g_{2} (\frac{7}{8}) + \frac{3}{8}

lo g_{10} (\frac{x}{z ^{5} y ^{3}})

2 lo g_{b} (x) + 4 lo g_{b} (z)

3 ln (x) - \frac{1}{2} ln (y) + 1

3 lo g_{4} (x) + 5 lo g_{4} (y) - 6 lo g_{4} (z)

lo g_{3} (z) + lo g_{3} (z + 5)

What is simplify-7/8 log_{2}(7/8)-1/8 log_{2}(1/8) ?
The solution to simplify-7/8 log_{2}(7/8)-1/8 log_{2}(1/8) is -7/8 log_{2}(7/8)+3/8