What is 2log_{5}(3x+2)-log_{5}(x+1) ?

The solution to 2log_{5}(3x+2)-log_{5}(x+1) is log_{5}(((3x+2)^2)/(x+1))

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simplify 2log_{5}(3x+2)-log_{5}(x+1)

simplify

2 lo g_{5} (3 x + 2) - lo g_{5} (x + 1)

lo g_{5} (\frac{( 3 x + 2 ) ^{2}}{x + 1})

Solution steps

2 lo g_{5} (3 x + 2) - lo g_{5} (x + 1)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{5} (3 x + 2) = lo g_{5} ((3 x + 2)^{2})

= lo g_{5} ((3 x + 2)^{2}) - lo g_{5} (x + 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{5} ((3 x + 2)^{2}) - lo g_{5} (x + 1) = lo g_{5} (\frac{( 3 x + 2 ) ^{2}}{x + 1})

= lo g_{5} (\frac{( 3 x + 2 ) ^{2}}{x + 1})

lo g_{3} (x (x + 1))

lo g_{5} (2 x)

lo g_{10} (z^{9} y)

lo g_{3} (4 ab)

3.79 + lo g_{10} (\frac{0.2 + 0.02}{0.5 - 0.02})

What is 2log_{5}(3x+2)-log_{5}(x+1) ?
The solution to 2log_{5}(3x+2)-log_{5}(x+1) is log_{5}(((3x+2)^2)/(x+1))