What is 3.79+log_{10}((0.2+0.02)/(0.5-0.02)) ?

The solution to 3.79+log_{10}((0.2+0.02)/(0.5-0.02)) is 3.79++log_{10}(0.2+0.02)-log_{10}(0.5-0.02)

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simplify 3.79+log_{10}((0.2+0.02)/(0.5-0.02))

simplify

3.79 + lo g_{10} (\frac{0.2 + 0.02}{0.5 - 0.02})

3.79 + + lo g_{10} (0.2 + 0.02) - lo g_{10} (0.5 - 0.02)

Decimal Notation

3.45118 \dots

Solution steps

3.79 + lo g_{10} (\frac{0.2 + 0.02}{0.5 - 0.02})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{0.2 + 0.02}{0.5 - 0.02}) = lo g_{10} (0.2 + 0.02) - lo g_{10} (0.5 - 0.02)

= 3.79 + + lo g_{10} (0.2 + 0.02) - lo g_{10} (0.5 - 0.02)

2 lo g_{5} (2) + 3 lo g_{5} (3)

lo g_{3} (9) + lo g_{4} (\frac{1}{6}) + lo g_{5} (1)

- \frac{1}{3} ln (\frac{1}{3})

lo g_{3} (\frac{1}{4} + 1) - lo g_{3} (\frac{1}{4})

\frac{1}{2} lo g_{9} (x) + lo g_{9} (y)

What is 3.79+log_{10}((0.2+0.02)/(0.5-0.02)) ?
The solution to 3.79+log_{10}((0.2+0.02)/(0.5-0.02)) is 3.79++log_{10}(0.2+0.02)-log_{10}(0.5-0.02)