What is expand log_{5}(x/(x+2)) ?

The solution to expand log_{5}(x/(x+2)) is log_{5}(x)-log_{5}(x+2)

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expand log_{5}(x/(x+2))

expand

lo g_{5} (\frac{x}{x + 2})

lo g_{5} (x) - lo g_{5} (x + 2)

Solution steps

lo g_{5} (\frac{x}{x + 2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{5} (\frac{x}{x + 2}) = lo g_{5} (x) - lo g_{5} (x + 2)

= lo g_{5} (x) - lo g_{5} (x + 2)

5 ln (\frac{0.7}{3})

- lo g_{10} (6.4 x 1 0^{- 5})

ln (\frac{81}{25})

(\frac{0.05916}{4}) ln (1.28 \cdot 1 0^{83})

lo g_{c} (x^{2} y^{2} z)

What is expand log_{5}(x/(x+2)) ?
The solution to expand log_{5}(x/(x+2)) is log_{5}(x)-log_{5}(x+2)