What is log_{2}(3)+log_{2}(5)+log_{2}(x-2) ?

The solution to log_{2}(3)+log_{2}(5)+log_{2}(x-2) is log_{2}(15(x-2))

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simplify log_{2}(3)+log_{2}(5)+log_{2}(x-2)

simplify

lo g_{2} (3) + lo g_{2} (5) + lo g_{2} (x - 2)

lo g_{2} (15 (x - 2))

Solution steps

lo g_{2} (3) + lo g_{2} (5) + lo g_{2} (x - 2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (3) + lo g_{2} (5) = lo g_{2} (3 \cdot 5)

= lo g_{2} (3 \cdot 5) + lo g_{2} (x - 2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (3 \cdot 5) + lo g_{2} (x - 2) = lo g_{2} (3 \cdot 5 (x - 2))

= lo g_{2} (3 \cdot 5 (x - 2))

Multiply the numbers:

3 \cdot 5 = 15

= lo g_{2} (15 (x - 2))

lo g_{10} (x (x^{2} + 2)^{\frac{1}{2}})

ln (x) - 3 [ln (x - 6) + ln (x + 6)]

lo g_{3} (\frac{y}{27})

lo g_{10} (\frac{27}{y})

0.935 - \frac{0.592}{2} lo g_{10} (\frac{0.2}{0. 1 ^{2}})

What is log_{2}(3)+log_{2}(5)+log_{2}(x-2) ?
The solution to log_{2}(3)+log_{2}(5)+log_{2}(x-2) is log_{2}(15(x-2))