What is log_{10}(8)-log_{10}(6) ?

The solution to log_{10}(8)-log_{10}(6) is log_{10}(4/3)

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simplify log_{10}(8)-log_{10}(6)

simplify

lo g_{10} (8) - lo g_{10} (6)

lo g_{10} (\frac{4}{3})

Decimal Notation

0.12493 \dots

Solution steps

lo g_{10} (8) - lo g_{10} (6)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (8) - lo g_{10} (6) = lo g_{10} (\frac{8}{6})

= lo g_{10} (\frac{8}{6})

Cancel

\frac{8}{6} : \frac{4}{3}

= lo g_{10} (\frac{4}{3})

lo g_{3} (3 - x) + lo g_{3} (4 - x)

lo g_{10} (\frac{y}{z ^{2}})

\frac{1}{5} [20 ln (n + 2) + ln (n) - ln (n^{5})]

\frac{1}{3} lo g_{3} (8) + lo g_{3} (6) - lo g_{3} (3)

lo g_{3} (81 x^{3} 1 + x^{2})

What is log_{10}(8)-log_{10}(6) ?
The solution to log_{10}(8)-log_{10}(6) is log_{10}(4/3)