What are the solutions to the equation 3x^2+11x+7=0 ?

The solutions to the equation 3x^2+11x+7=0 are x=(-11+sqrt(37))/6 ,x=(-11-sqrt(37))/6

Find the zeros of 3x^2+11x+7=0

The zeros of 3x^2+11x+7=0 are x=(-11+sqrt(37))/6 ,x=(-11-sqrt(37))/6

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3 x^{2} + 11 x + 7 = 0

x = \frac{- 11 + 37}{6}, x = \frac{- 11 - 37}{6}

Decimal Notation

x = - 0.81953 \dots, x = - 2.84712 \dots

Solution steps

3 x^{2} + 11 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

1 1^{2} - 4 \cdot 3 \cdot 7 = 37

x_{1, 2} = \frac{- 11 \pm 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 11 + 37}{2 \cdot 3}, x_{2} = \frac{- 11 - 37}{2 \cdot 3}

x = \frac{- 11 + 37}{2 \cdot 3} : \frac{- 11 + 37}{6}

x = \frac{- 11 - 37}{2 \cdot 3} : \frac{- 11 - 37}{6}

The solutions to the quadratic equation are:

x = \frac{- 11 + 37}{6}, x = \frac{- 11 - 37}{6}

2 x^{2} + 5 x + 20 = 0

x, z = x^{2} + y^{2}

x^{2} + 9 x - 13 = 0

x^{2} - 2 x

r, A = π r^{2}

What are the solutions to the equation 3x^2+11x+7=0 ?
The solutions to the equation 3x^2+11x+7=0 are x=(-11+sqrt(37))/6 ,x=(-11-sqrt(37))/6
Find the zeros of 3x^2+11x+7=0
The zeros of 3x^2+11x+7=0 are x=(-11+sqrt(37))/6 ,x=(-11-sqrt(37))/6