What are the solutions to the equation 6x^2+11bx=10b^2 ?

The solutions to the equation 6x^2+11bx=10b^2 are x=(2b)/3 ,x=-(5b)/2

Find the zeros of 6x^2+11bx=10b^2

The zeros of 6x^2+11bx=10b^2 are x=(2b)/3 ,x=-(5b)/2

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6 x^{2} + 11 b x = 10 b^{2}

x = \frac{2 b}{3}, x = - \frac{5 b}{2}

Solution steps

6 x^{2} + 11 b x = 10 b^{2}

Move

10 b^{2}

to the left side

6 x^{2} + 11 b x - 10 b^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 b \pm ( 11 b ) ^{2} - 4 \cdot 6 ( - 10 b ^{2} )}{2 \cdot 6}

Simplify

(11 b)^{2} - 4 \cdot 6 (- 10 b^{2}) : 19 b

x_{1, 2} = \frac{- 11 b \pm 19 b}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 11 b + 19 b}{2 \cdot 6}, x_{2} = \frac{- 11 b - 19 b}{2 \cdot 6}

x = \frac{- 11 b + 19 b}{2 \cdot 6} : \frac{2 b}{3}

x = \frac{- 11 b - 19 b}{2 \cdot 6} : - \frac{5 b}{2}

The solutions to the quadratic equation are:

x = \frac{2 b}{3}, x = - \frac{5 b}{2}

- 2 x^{2} + 23 = 7

4 x^{2} = - 4 x - 17

s^{2} + 2 s + 5

- 3 x^{2} + 12 = 0

x^{2} = - 9 x + 8

What are the solutions to the equation 6x^2+11bx=10b^2 ?
The solutions to the equation 6x^2+11bx=10b^2 are x=(2b)/3 ,x=-(5b)/2
Find the zeros of 6x^2+11bx=10b^2
The zeros of 6x^2+11bx=10b^2 are x=(2b)/3 ,x=-(5b)/2