What are the solutions to the equation 5x^2+4=2(x+2) ?

The solutions to the equation 5x^2+4=2(x+2) are x= 2/5 ,x=0

Find the zeros of 5x^2+4=2(x+2)

The zeros of 5x^2+4=2(x+2) are x= 2/5 ,x=0

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5 x^{2} + 4 = 2 (x + 2)

x = \frac{2}{5}, x = 0

Decimal Notation

x = 0.4, x = 0

Solution steps

5 x^{2} + 4 = 2 (x + 2)

Expand

2 (x + 2) : 2 x + 4

5 x^{2} + 4 = 2 x + 4

Move

4

to the left side

5 x^{2} = 2 x

Move

2 x

to the left side

5 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 5}

x = \frac{- ( - 2 ) + 2}{2 \cdot 5} : \frac{2}{5}

x = \frac{- ( - 2 ) - 2}{2 \cdot 5} : 0

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = 0

6 + 2 x^{2} = 20

x^{2} + 14 x

(x - 3)^{2} - (2 x + 5)^{2} = - 16

12 - x^{2} = - 3

x, x^{2} + x y + y^{2} = 3

What are the solutions to the equation 5x^2+4=2(x+2) ?
The solutions to the equation 5x^2+4=2(x+2) are x= 2/5 ,x=0
Find the zeros of 5x^2+4=2(x+2)
The zeros of 5x^2+4=2(x+2) are x= 2/5 ,x=0