What are the solutions to the equation 4x^2+9=-4x ?

The solutions to the equation 4x^2+9=-4x are x=-1/2+sqrt(2)i,x=-1/2-sqrt(2)i

Find the zeros of 4x^2+9=-4x

The zeros of 4x^2+9=-4x are x=-1/2+sqrt(2)i,x=-1/2-sqrt(2)i

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4 x^{2} + 9 = - 4 x

x = - \frac{1}{2} + 2 i, x = - \frac{1}{2} - 2 i

Solution steps

4 x^{2} + 9 = - 4 x

Move

4 x

to the left side

4 x^{2} + 9 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 4 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

Simplify

4^{2} - 4 \cdot 4 \cdot 9 : 82 i

x_{1, 2} = \frac{- 4 \pm 8 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 8 2 i}{2 \cdot 4}, x_{2} = \frac{- 4 - 8 2 i}{2 \cdot 4}

x = \frac{- 4 + 8 2 i}{2 \cdot 4} : - \frac{1}{2} + 2 i

x = \frac{- 4 - 8 2 i}{2 \cdot 4} : - \frac{1}{2} - 2 i

The solutions to the quadratic equation are:

x = - \frac{1}{2} + 2 i, x = - \frac{1}{2} - 2 i

- 6 x^{2} + 103 x - 17 = 0

n^{2} - 6 = - n

2 x^{2} + 11 = 131

w^{2} - \frac{1}{15} w = \frac{2}{15}

x^{2} + 5 x

What are the solutions to the equation 4x^2+9=-4x ?
The solutions to the equation 4x^2+9=-4x are x=-1/2+sqrt(2)i,x=-1/2-sqrt(2)i
Find the zeros of 4x^2+9=-4x
The zeros of 4x^2+9=-4x are x=-1/2+sqrt(2)i,x=-1/2-sqrt(2)i