What are the solutions to the equation 4x^2+12x=135 ?

The solutions to the equation 4x^2+12x=135 are x= 9/2 ,x=-15/2

Find the zeros of 4x^2+12x=135

The zeros of 4x^2+12x=135 are x= 9/2 ,x=-15/2

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4 x^{2} + 12 x = 135

x = \frac{9}{2}, x = - \frac{15}{2}

Decimal Notation

x = 4.5, x = - 7.5

Solution steps

4 x^{2} + 12 x = 135

Move

135

to the left side

4 x^{2} + 12 x - 135 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 135 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 135) = 48

x_{1, 2} = \frac{- 12 \pm 48}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 48}{2 \cdot 4}, x_{2} = \frac{- 12 - 48}{2 \cdot 4}

x = \frac{- 12 + 48}{2 \cdot 4} : \frac{9}{2}

x = \frac{- 12 - 48}{2 \cdot 4} : - \frac{15}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - \frac{15}{2}

x^{2} + 37 = - 14 x

m^{2} + 10 m + 21 = 0

x^{2} - 5 x + 6 = 0

x^{2} + 18 x

6 x^{2} - 2 = 0

What are the solutions to the equation 4x^2+12x=135 ?
The solutions to the equation 4x^2+12x=135 are x= 9/2 ,x=-15/2
Find the zeros of 4x^2+12x=135
The zeros of 4x^2+12x=135 are x= 9/2 ,x=-15/2