What are the solutions to the equation 2(x+2)^2-23=-17 ?

The solutions to the equation 2(x+2)^2-23=-17 are x=sqrt(3)-2,x=-sqrt(3)-2

Find the zeros of 2(x+2)^2-23=-17

The zeros of 2(x+2)^2-23=-17 are x=sqrt(3)-2,x=-sqrt(3)-2

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2 (x + 2)^{2} - 23 = - 17

x = 3 - 2, x = - 3 - 2

Decimal Notation

x = - 0.26794 \dots, x = - 3.73205 \dots

Solution steps

2 (x + 2)^{2} - 23 = - 17

Move

23

to the right side

2 (x + 2)^{2} = 6

Divide both sides by

2

(x + 2)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 3 : x = 3 - 2

Solve

x + 2 = - 3 : x = - 3 - 2

The solutions to the quadratic equation are:

x = 3 - 2, x = - 3 - 2

z^{2} = - 1

x^{2} = 5^{2} + 1 2^{2}

x^{2} - 289 = 0

4 (x + 7)^{2} - 49 = - 13

x^{2} - 6 x + 9 = 256

What are the solutions to the equation 2(x+2)^2-23=-17 ?
The solutions to the equation 2(x+2)^2-23=-17 are x=sqrt(3)-2,x=-sqrt(3)-2
Find the zeros of 2(x+2)^2-23=-17
The zeros of 2(x+2)^2-23=-17 are x=sqrt(3)-2,x=-sqrt(3)-2