What are the solutions to the equation 2x^2+x-11=6x-8 ?

The solutions to the equation 2x^2+x-11=6x-8 are x=3,x=-1/2

Find the zeros of 2x^2+x-11=6x-8

The zeros of 2x^2+x-11=6x-8 are x=3,x=-1/2

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2 x^{2} + x - 11 = 6 x - 8

x = 3, x = - \frac{1}{2}

Decimal Notation

x = 3, x = - 0.5

Solution steps

2 x^{2} + x - 11 = 6 x - 8

Move

8

to the left side

2 x^{2} + x - 3 = 6 x

Move

6 x

to the left side

2 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

x = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

x = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{2}

x^{2} + 20 x + 101 = 0

x^{2} + 118 = 20 x

a x^{2} + b x + c

x^{2} + 10 x = - 16

x, x^{2} + y^{2} + z^{2} = 25

What are the solutions to the equation 2x^2+x-11=6x-8 ?
The solutions to the equation 2x^2+x-11=6x-8 are x=3,x=-1/2
Find the zeros of 2x^2+x-11=6x-8
The zeros of 2x^2+x-11=6x-8 are x=3,x=-1/2