What are the solutions to the equation 5-3(x-4)^2=0 ?

The solutions to the equation 5-3(x-4)^2=0 are x=sqrt(5/3)+4,x=-sqrt(5/3)+4

Find the zeros of 5-3(x-4)^2=0

The zeros of 5-3(x-4)^2=0 are x=sqrt(5/3)+4,x=-sqrt(5/3)+4

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5 - 3 (x - 4)^{2} = 0

x = \frac{5}{3} + 4, x = - \frac{5}{3} + 4

Decimal Notation

x = 5.29099 \dots, x = 2.70900 \dots

Solution steps

5 - 3 (x - 4)^{2} = 0

Move

5

to the right side

- 3 (x - 4)^{2} = - 5

Divide both sides by

- 3

(x - 4)^{2} = \frac{5}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = \frac{5}{3} : x = \frac{5}{3} + 4

Solve

x - 4 = - \frac{5}{3} : x = - \frac{5}{3} + 4

The solutions to the quadratic equation are:

x = \frac{5}{3} + 4, x = - \frac{5}{3} + 4

x^{2} = 6^{2} + 8^{2}

25 x^{2} - 40 x + 17 = 0

a^{2} - 2 a + 1 = 3

x^{2} = 6 x + 1

3 x^{2} - 27 x - 18 = 0

What are the solutions to the equation 5-3(x-4)^2=0 ?
The solutions to the equation 5-3(x-4)^2=0 are x=sqrt(5/3)+4,x=-sqrt(5/3)+4
Find the zeros of 5-3(x-4)^2=0
The zeros of 5-3(x-4)^2=0 are x=sqrt(5/3)+4,x=-sqrt(5/3)+4