What are the solutions to the equation (2x+3)(2x-3)=0 ?

The solutions to the equation (2x+3)(2x-3)=0 are x=-3/2 ,x= 3/2

Find the zeros of (2x+3)(2x-3)=0

The zeros of (2x+3)(2x-3)=0 are x=-3/2 ,x= 3/2

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(2 x + 3) (2 x - 3) = 0

x = - \frac{3}{2}, x = \frac{3}{2}

Decimal Notation

x = - 1.5, x = 1.5

Solution steps

(2 x + 3) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or 2 x - 3 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = \frac{3}{2}

x, x^{2} - x y + y^{2} = 7

- 7 x^{2} + 17 x + 12 = 0

4 - 2 a^{2} = - 7

x, 8 x^{2} - 6 y^{2} - 16 x + 24 y - 16 = 0

(4 x - 3) (5 x - 4) = 0

What are the solutions to the equation (2x+3)(2x-3)=0 ?
The solutions to the equation (2x+3)(2x-3)=0 are x=-3/2 ,x= 3/2
Find the zeros of (2x+3)(2x-3)=0
The zeros of (2x+3)(2x-3)=0 are x=-3/2 ,x= 3/2