What are the solutions to the equation 3(x+1)^2-15=-12 ?

The solutions to the equation 3(x+1)^2-15=-12 are x=0,x=-2

Find the zeros of 3(x+1)^2-15=-12

The zeros of 3(x+1)^2-15=-12 are x=0,x=-2

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3 (x + 1)^{2} - 15 = - 12

x = 0, x = - 2

Solution steps

3 (x + 1)^{2} - 15 = - 12

Move

15

to the right side

3 (x + 1)^{2} = 3

Divide both sides by

3

(x + 1)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 1 : x = 0

Solve

x + 1 = - 1 : x = - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

3 x^{2} - 30 = 0

x^{2} - 40 = 9

4 x^{2} - 12 x = - 17

x^{2} - 2 x = 7

a, y = (a - \frac{b}{x})^{2}

What are the solutions to the equation 3(x+1)^2-15=-12 ?
The solutions to the equation 3(x+1)^2-15=-12 are x=0,x=-2
Find the zeros of 3(x+1)^2-15=-12
The zeros of 3(x+1)^2-15=-12 are x=0,x=-2