What are the solutions to the equation solvefor x,4x^2-9y^2-16x-18y+7=0 ?

The solutions to the equation solvefor x,4x^2-9y^2-16x-18y+7=0 are x=(3y+7)/2 ,x=(-3y+1)/2

Find the zeros of solvefor x,4x^2-9y^2-16x-18y+7=0

The zeros of solvefor x,4x^2-9y^2-16x-18y+7=0 are x=(3y+7)/2 ,x=(-3y+1)/2

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solve for

x, 4 x^{2} - 9 y^{2} - 16 x - 18 y + 7 = 0

x = \frac{3 y + 7}{2}, x = \frac{- 3 y + 1}{2}

Solution steps

4 x^{2} - 9 y^{2} - 16 x - 18 y + 7 = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 16 x - 9 y^{2} - 18 y + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 ( - 9 y ^{2} - 18 y + 7 )}{2 \cdot 4}

Simplify

(- 16)^{2} - 4 \cdot 4 (- 9 y^{2} - 18 y + 7) : 12 (y + 1)

x_{1, 2} = \frac{- ( - 16 ) \pm 12 ( y + 1 )}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 12 ( y + 1 )}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 12 ( y + 1 )}{2 \cdot 4}

x = \frac{- ( - 16 ) + 12 ( y + 1 )}{2 \cdot 4} : \frac{3 y + 7}{2}

x = \frac{- ( - 16 ) - 12 ( y + 1 )}{2 \cdot 4} : \frac{- 3 y + 1}{2}

The solutions to the quadratic equation are:

x = \frac{3 y + 7}{2}, x = \frac{- 3 y + 1}{2}

5 x^{2} - 30 x + 40 = 0

2 x^{2} + 12 x + 56 = 0

b, s (t) = b^{2}

x^{2} - 3 x - 4 = 0

5 x^{2} + 10 x - 9 = 3 x - 3

What are the solutions to the equation solvefor x,4x^2-9y^2-16x-18y+7=0 ?
The solutions to the equation solvefor x,4x^2-9y^2-16x-18y+7=0 are x=(3y+7)/2 ,x=(-3y+1)/2
Find the zeros of solvefor x,4x^2-9y^2-16x-18y+7=0
The zeros of solvefor x,4x^2-9y^2-16x-18y+7=0 are x=(3y+7)/2 ,x=(-3y+1)/2