What are the solutions to the equation 14x^2+17x-6=0 ?

The solutions to the equation 14x^2+17x-6=0 are x= 2/7 ,x=-3/2

Find the zeros of 14x^2+17x-6=0

The zeros of 14x^2+17x-6=0 are x= 2/7 ,x=-3/2

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14 x^{2} + 17 x - 6 = 0

x = \frac{2}{7}, x = - \frac{3}{2}

Decimal

x = 0.28571 \dots, x = - 1.5

Solution steps

14 x^{2} + 17 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 14 ( - 6 )}{2 \cdot 14}

1 7^{2} - 4 \cdot 14 (- 6) = 25

x_{1, 2} = \frac{- 17 \pm 25}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- 17 + 25}{2 \cdot 14}, x_{2} = \frac{- 17 - 25}{2 \cdot 14}

x = \frac{- 17 + 25}{2 \cdot 14} : \frac{2}{7}

x = \frac{- 17 - 25}{2 \cdot 14} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{2}{7}, x = - \frac{3}{2}

x^{2} - 16 x + 4 = 0

x, x^{2} + 4 x k + 1 = 0

x, y^{2} (x^{2} - 1) - 2 x = 0

2 x^{2} + 20 x = - 10

n^{2} = - 144

What are the solutions to the equation 14x^2+17x-6=0 ?
The solutions to the equation 14x^2+17x-6=0 are x= 2/7 ,x=-3/2
Find the zeros of 14x^2+17x-6=0
The zeros of 14x^2+17x-6=0 are x= 2/7 ,x=-3/2