What are the solutions to the equation 3(4x+1)^2-37=5 ?

The solutions to the equation 3(4x+1)^2-37=5 are x=(sqrt(14)-1)/4 ,x=(-sqrt(14)-1)/4

Find the zeros of 3(4x+1)^2-37=5

The zeros of 3(4x+1)^2-37=5 are x=(sqrt(14)-1)/4 ,x=(-sqrt(14)-1)/4

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3 (4 x + 1)^{2} - 37 = 5

x = \frac{14 - 1}{4}, x = \frac{- 14 - 1}{4}

Decimal Notation

x = 0.68541 \dots, x = - 1.18541 \dots

Solution steps

3 (4 x + 1)^{2} - 37 = 5

Move

37

to the right side

3 (4 x + 1)^{2} = 42

Divide both sides by

3

(4 x + 1)^{2} = 14

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 1 = 14 : x = \frac{14 - 1}{4}

Solve

4 x + 1 = - 14 : x = \frac{- 14 - 1}{4}

The solutions to the quadratic equation are:

x = \frac{14 - 1}{4}, x = \frac{- 14 - 1}{4}

x^{2} - 3 x - 10 = 0

3 x^{2} + 2 x = 6

4 (4 x + 9)^{2} - 17 = - 5

- 6 x^{2} - 7 x + 155 = - 8 x

a^{2} - 2 a - 3 = 0

What are the solutions to the equation 3(4x+1)^2-37=5 ?
The solutions to the equation 3(4x+1)^2-37=5 are x=(sqrt(14)-1)/4 ,x=(-sqrt(14)-1)/4
Find the zeros of 3(4x+1)^2-37=5
The zeros of 3(4x+1)^2-37=5 are x=(sqrt(14)-1)/4 ,x=(-sqrt(14)-1)/4