What are the solutions to the equation 4^2+4^2=c^2 ?

The solutions to the equation 4^2+4^2=c^2 are c=4sqrt(2),c=-4sqrt(2)

Find the zeros of 4^2+4^2=c^2

The zeros of 4^2+4^2=c^2 are c=4sqrt(2),c=-4sqrt(2)

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4^{2} + 4^{2} = c^{2}

c = 42, c = - 42

Decimal

c = 5.65685 \dots, c = - 5.65685 \dots

Solution steps

4^{2} + 4^{2} = c^{2}

Switch sides

c^{2} = 4^{2} + 4^{2}

Simplify

4^{2} + 4^{2} : 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 32, c = - 32

32 = 42

- 32 = - 42

c = 42, c = - 42

r^{2} + 2 r - 33 = 0

12 x^{2} + 27 x + 15

4 x - 5 + 2 (x - 3) = 12 x + 7

2 x^{2} - 6 x = - 5

\frac{x ^{\frac{1}{2}} y ^{2}}{4 x ^{5} y}

What are the solutions to the equation 4^2+4^2=c^2 ?
The solutions to the equation 4^2+4^2=c^2 are c=4sqrt(2),c=-4sqrt(2)
Find the zeros of 4^2+4^2=c^2
The zeros of 4^2+4^2=c^2 are c=4sqrt(2),c=-4sqrt(2)