What are the solutions to the equation -2x^2+6x=0 ?

The solutions to the equation -2x^2+6x=0 are x=0,x=3

Find the zeros of -2x^2+6x=0

The zeros of -2x^2+6x=0 are x=0,x=3

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- 2 x^{2} + 6 x = 0

x = 0, x = 3

Solution steps

- 2 x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

6^{2} - 4 (- 2) \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 ( - 2 )}, x_{2} = \frac{- 6 - 6}{2 ( - 2 )}

x = \frac{- 6 + 6}{2 ( - 2 )} : 0

x = \frac{- 6 - 6}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

x, f = - 2 x y^{3} + 5 y^{2} - x^{2} y^{2} - 10

4 (x + 4)^{2} + 23 = 27

x, x y^{2} - x^{2} y + 6 = 0

2 x^{2} + 20 x + 50 = 0

5 a^{2} - 2 a = - 16

What are the solutions to the equation -2x^2+6x=0 ?
The solutions to the equation -2x^2+6x=0 are x=0,x=3
Find the zeros of -2x^2+6x=0
The zeros of -2x^2+6x=0 are x=0,x=3