What are the solutions to the equation 2x^2+20x+50=0 ?

The solutions to the equation 2x^2+20x+50=0 are x=-5

Find the zeros of 2x^2+20x+50=0

The zeros of 2x^2+20x+50=0 are x=-5

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2 x^{2} + 20 x + 50 = 0

x = - 5

Solution steps

2 x^{2} + 20 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 50}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 \cdot 50 = 0

x_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 2}

x = \frac{- 20}{2 \cdot 2}

\frac{- 20}{2 \cdot 2} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

5 a^{2} - 2 a = - 16

y, y = x^{2} + y

m^{2} - 6 m - 17 = - 5

1.15 (0.85 - 2 x)^{2} = x

5 n^{2} - 2 = - 92

What are the solutions to the equation 2x^2+20x+50=0 ?
The solutions to the equation 2x^2+20x+50=0 are x=-5
Find the zeros of 2x^2+20x+50=0
The zeros of 2x^2+20x+50=0 are x=-5