What are the solutions to the equation 25(1-2x)^2-43=-7 ?

The solutions to the equation 25(1-2x)^2-43=-7 are x=-1/10 ,x= 11/10

Find the zeros of 25(1-2x)^2-43=-7

The zeros of 25(1-2x)^2-43=-7 are x=-1/10 ,x= 11/10

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25 (1 - 2 x)^{2} - 43 = - 7

x = - \frac{1}{10}, x = \frac{11}{10}

Decimal Notation

x = - 0.1, x = 1.1

Solution steps

25 (1 - 2 x)^{2} - 43 = - 7

Move

43

to the right side

25 (1 - 2 x)^{2} = 36

Divide both sides by

25

(1 - 2 x)^{2} = \frac{36}{25}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - 2 x = \frac{36}{25} : x = - \frac{1}{10}

Solve

1 - 2 x = - \frac{36}{25} : x = \frac{11}{10}

The solutions to the quadratic equation are:

x = - \frac{1}{10}, x = \frac{11}{10}

5 x^{2} + 8 x - 11 = 0

x^{2} = 6 x - 11

4 x^{2} + 24 x - 12 = 0

x, x^{2} + x y + y^{3} = 1

(x - 3)^{2} + 27 = 0

What are the solutions to the equation 25(1-2x)^2-43=-7 ?
The solutions to the equation 25(1-2x)^2-43=-7 are x=-1/10 ,x= 11/10
Find the zeros of 25(1-2x)^2-43=-7
The zeros of 25(1-2x)^2-43=-7 are x=-1/10 ,x= 11/10