What are the solutions to the equation 4x^2+24x-12=0 ?

The solutions to the equation 4x^2+24x-12=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)

Find the zeros of 4x^2+24x-12=0

The zeros of 4x^2+24x-12=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)

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4 x^{2} + 24 x - 12 = 0

x = - 3 + 23, x = - 3 - 23

Decimal Notation

x = 0.46410 \dots, x = - 6.46410 \dots

Solution steps

4 x^{2} + 24 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 ( - 12 )}{2 \cdot 4}

2 4^{2} - 4 \cdot 4 (- 12) = 163

x_{1, 2} = \frac{- 24 \pm 16 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 24 + 16 3}{2 \cdot 4}, x_{2} = \frac{- 24 - 16 3}{2 \cdot 4}

x = \frac{- 24 + 16 3}{2 \cdot 4} : - 3 + 23

x = \frac{- 24 - 16 3}{2 \cdot 4} : - 3 - 23

The solutions to the quadratic equation are:

x = - 3 + 23, x = - 3 - 23

x, x^{2} + x y + y^{3} = 1

(x - 3)^{2} + 27 = 0

3 x^{2} - 42 x = - 87

x, x^{2} + x y + y^{2} = 0

x^{2} - 10 x + 5

What are the solutions to the equation 4x^2+24x-12=0 ?
The solutions to the equation 4x^2+24x-12=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)
Find the zeros of 4x^2+24x-12=0
The zeros of 4x^2+24x-12=0 are x=-3+2sqrt(3),x=-3-2sqrt(3)