What are the solutions to the equation 8-((x+4)(x-8))/3 =-2x ?

The solutions to the equation 8-((x+4)(x-8))/3 =-2x are x=-4,x=14

Find the zeros of 8-((x+4)(x-8))/3 =-2x

The zeros of 8-((x+4)(x-8))/3 =-2x are x=-4,x=14

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8 - \frac{( x + 4 ) ( x - 8 )}{3} = - 2 x

x = - 4, x = 14

Solution steps

8 - \frac{( x + 4 ) ( x - 8 )}{3} = - 2 x

Multiply both sides by

3

24 - (x + 4) (x - 8) = - 6 x

Expand

24 - (x + 4) (x - 8) : - x^{2} + 4 x + 56

- x^{2} + 4 x + 56 = - 6 x

Move

6 x

to the left side

- x^{2} + 10 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) \cdot 56}{2 ( - 1 )}

1 0^{2} - 4 (- 1) \cdot 56 = 18

x_{1, 2} = \frac{- 10 \pm 18}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 18}{2 ( - 1 )}, x_{2} = \frac{- 10 - 18}{2 ( - 1 )}

x = \frac{- 10 + 18}{2 ( - 1 )} : - 4

x = \frac{- 10 - 18}{2 ( - 1 )} : 14

The solutions to the quadratic equation are:

x = - 4, x = 14

5 x^{2} + 70 x - 1355 = 0

x^{2} + 12 x + 36 = 100

x^{2} + 4 x - 7

24 = x^{2} - 4 x + 3

x, x^{2} y^{2} - x y + x = 1

What are the solutions to the equation 8-((x+4)(x-8))/3 =-2x ?
The solutions to the equation 8-((x+4)(x-8))/3 =-2x are x=-4,x=14
Find the zeros of 8-((x+4)(x-8))/3 =-2x
The zeros of 8-((x+4)(x-8))/3 =-2x are x=-4,x=14